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Question

If f(t) = 4t2 − 3t + 6, find (i) f(0), (ii) f(4), (iii) f(−5).

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Solution

i ft=4t2-3t+6f0=4×02-3×0+6
=0-0+6=6

ii ft=4t2-3t+6f4=4×42-3×4+6
=64-12+6=58

iii ft=4t2-3t+6f-5=4×-52-3×-5+6
=100+15+6=121

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