You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Functions

If fx=2x3+3...

Question

If $f (x) = 2 x^{3} + 3 x^{2} + c x + 8$ , where $c$ is a constant. The graph of $f$ intersects the x-axis at the three points $(- 4, 0) (\frac{1}{2}, 0)$ and $(p, 0)$ . Find the value of $c$ .

- 18

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 18$
$- 4 i s r o o t o f e q u a t i o n (a s i t i n t e r s e c t t h e x - a x i s a t (- 4, 0)) 2 x^{3} + 3 x^{2} + c x + 8 S o f (- 4) = 0 2 (- 4)^{3} + 3 {(- 4)}^{2} + c (- 4) + 8 = 0 O n s o l v i n g c = - 18$

Suggest Corrections

Similar questions

f (x) = 2 x^{3} + 3 x^{2} + c x + 8

(- 4, 0), (\frac{1}{2}, 0)

f (x) = 2 x^{3} - 3 x^{2_{-}} 12 x + 8

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 8, f^{'} (2) = 0

f^{''} (2) > 0

y = a x^{3} + b x^{2} + c x + 8

x

P (- 2, 0)

y

Q (0, 8)

a

b

c

y = a x^{3} + b x^{2} + c x + 5

P (- 2, 0)

Q

3

a, b, c

2 x + k y = 10 k

x

(2, 0)

k

Join BYJU'S Learning Program