Question

If $f\left(x\right)=2017\times tanx+3x^{3}sinx+x^{2018}+2x^3$ then find $f^{\prime }\left(x\right)$.

Answer 1

Given, $y=2017\tan x+3x^3\sin x+x^{2018}+2x^3$

Let, $y=f\left(x\right)$;

Now, differentiation both sides w.r.t. 'x', we get,

$f^{\prime }\left(x\right)=2017{\sec }^{2}x+9x^2\sin x+3x^3\cos x+2018x^{2077}+6x^2$.