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Question

If f(x)=ax+ax2 and f(x+y)+f(xy)=kf(x)f(y), then k is equal to

A
2
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B
4
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C
2
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D
None of these
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Solution

The correct option is A 2
Given, f(x)=ax+ax2
On putting y=0, in the given relation, we f(x)+f(x)=kf(x)f(0)
2f(x)=kf(x) .....[f(0)=1]
k=2

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