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Byju's Answer
Standard XII
Mathematics
Graph of Trigonometric Ratios
If f x =sin l...
Question
If
f
(
x
)
=
sin
(
log
x
)
and
g
(
x
)
=
cos
(
sin
x
)
are two functions such that
(
f
(
x
)
)
2
+
(
g
(
x
)
)
2
=
1
,
then the number of maximum possible real values of
x
is
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Solution
(
f
(
x
)
)
2
+
(
g
(
x
)
)
2
=
1
⋯
(
1
)
⇒
sin
2
(
log
x
)
+
cos
2
(
sin
x
)
=
1
We know that
sin
2
x
+
cos
2
x
=
1
for all real values of
x
So, equation
(
1
)
is possible only if
log
x
=
sin
x
Clearly, there is only one possible solution.
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0
Similar questions
Q.
Let f be twice differentiable function such that
f
′′
(
x
)
=
−
f
(
x
)
and
f
′
(
x
)
=
g
(
x
)
,
h
(
x
)
=
f
(
x
)
2
+
g
(
x
)
2
. If
h
(
5
)
=
11
then
h
(
10
)
is equal to
Q.
Let
f
be twice differentiable function such that
f
"
(
x
)
=
−
f
(
x
)
and
f
′
(
x
)
=
g
(
x
)
,
h
(
x
)
=
[
f
(
x
)
2
+
g
(
x
)
2
]
,
h
(
5
)
=
11
, then
h
(
10
)
is equal to
Q.
Given functions f and g such that for all x,
(
g
(
x
)
)
2
−
(
f
(
x
)
)
2
=
1
,
f
′
(
x
)
=
(
g
(
x
)
)
2
and f''(x) and g''(x) exist g(x) < 0, f(0) = 0 then which is true
Q.
Let
f
be the twice differentiable function such that
f
′′
(
x
)
=
−
f
(
x
)
and
f
′
(
x
)
=
g
(
x
)
. If
h
′
(
x
)
=
[
f
(
x
)
2
+
g
(
x
)
2
]
,
h
(
1
)
=
8
,
h
(
0
)
=
2
, then
h
(
2
)
equals to
Q.
Let f(x) and g(x) be two continuous functions defined from
R
→
R
, such that
f
(
x
1
)
>
f
(
x
2
)
and
g
(
x
1
)
<
g
(
x
2
)
,
∀
x
1
>
x
2
then solution set of
f
(
g
(
α
2
−
2
α
)
)
>
f
(
g
(
3
α
−
4
)
)
is
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