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Question

If f(x)=x2+2x+2;x1=x3+3x+1;x<1, then the value of f(f(2)) is :

A
15
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B
17
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C
22
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D
None of these
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Solution

The correct option is B 17
f(x)={x2+2x+2;x1x3+3x+1;x<1
f(2)=(2)3+3(2)+1=86+1=3
f(f(2))=f(3)=(3)2+2(3)+2=17
Answer option: (B).

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