If f(x) = $x^{3} + a x^{2} + b x + c$ is minimum at x = 3 and maximum at x = -1, then-

A = -3, b = -9, c = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A = 3, b = 9, c = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A = -3, b= -9,

c \in R

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C A = -3, b= -9, $c \in R$

Suggest Corrections

Similar questions

-

f (x) = x^{3} + a x^{2} + b x + c

x = - 1

x = 3

-

-

f (x) = x^{3} + a x^{2} + b x + c

x = - 1

x = 3

a, b, c

$Find x : \frac{x - b - c}{a} + \frac{x - c - a}{b} + \frac{x - a - b}{c} = 3, if \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \neq 0$

Join BYJU'S Learning Program