If fx-x- x - 1- and fx-x2-b x-c- x-1- and f-x exists finitely for all x - R- then

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Evaluation of a Determinant

If fx=x, x ≤ ...

Question

If f(x) = x, x≤1, and f(x) =x² + bx + c, x>1, and f'(x) exists finitely for all x ϵ R, then

b =-1, c ϵ R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

c = 1, b ϵ R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b = 1, c =-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b =-1, c =1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = {\begin{matrix} x; x \leq 1 x^{2} + b x + c; x > 1 \end{matrix}

f^{'} (x)

x \in R

f^{'} (x)

x \in R

g (x) = f (x) - (f (x))^{2} + (f (x))^{3}

x \in R

f (x) > 0

x

f^{'} (x)

x

f

h

h^{'} (x) = \frac{1}{1 + log x}

f^{'} (x)

If [.] denotes greatest integer function and f(x) = [x] ${\frac{s i n \frac{π}{[x + 1]} + s i n π [x + 1]}{1 + [x]}},$ then

f (x) = x - x^{2} + x^{3} - x^{4} + \dots

| x | < 1

f^{'} (x) =

Join BYJU'S Learning Program