If ab+ba=1, then a3+b3=
1
-1
12
0
ab+ba=1⇒ a2+b2ab=1⇒ a2+b2=−ab⇒ a2+b2+ab=0⇒ a2+ab+b2=0Now ,a3−b3=(a−b)(a2+ab+b2)=(a−b)×0
If ab+ba=1, then the value of a3+b3 is