If (h,k) is the centre of x2 + y2 − 2x − 4y + 11 = 0, find the value of h2 + k2 + hk.
The centre of the circle x2 + y2 + 2gx + 2fy + c = 0 is (−g,−f).
Equation of the given circle is x2 + y2 - 2x - 4y + 11 = 0
⇒ g = -1 and f = -2
⇒ centre ≡ (1,2)
⇒ Answer =1 + 4 + 2 = 7