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Standard IX

Mathematics

Zeroes of a Polynomial

If hx = x2 ...

Question

If $h (x) = x^{2} - 3 x + 1$ , what is $[h (- 2)^{2}]$ ?

- 9

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5

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11

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81

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121

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Solution

The correct option is E $121$

Given, $h (x) = x^{2} - 3 x + 1$

$[h (- 2)^{2}] = ?$

$x = - 2$

So, $h (- 2) = (- 2)^{2} - 3 (- 2) + 1$

$\Rightarrow h (- 2) = 4 + 6 + 1 \Rightarrow 11$

$\Rightarrow [h (- 2)^{2}] = 11^{2} = 121$

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If h(x)=x2−3x+1, what is [h(−2)2]?

The correct option is E 121 Given, h(x)=x2−3x+1 [h(−2)2]=? x=−2 So, h(−2)=(−2)2−3(−2)+1 ⇒h(−2)=4+6+1⇒11 ⇒[h(−2)2]=112=121

If $h (x) = x^{2} - 3 x + 1$ , what is $[h (- 2)^{2}]$ ?

The correct option is E $121$

Given, $h (x) = x^{2} - 3 x + 1$

$[h (- 2)^{2}] = ?$

$x = - 2$

So, $h (- 2) = (- 2)^{2} - 3 (- 2) + 1$

$\Rightarrow h (- 2) = 4 + 6 + 1 \Rightarrow 11$

$\Rightarrow [h (- 2)^{2}] = 11^{2} = 121$