If lint 0- pi - X - f sin x d x - Alint 0- frac pi 2- f sin x d x - then A -A- 0B- 2 -C- -D- - - 4

The correct option is C π I=∫_0^πxf(sinx)dx=π∫_0^π/2 f(sinx)dx ⇒ A=π ...

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Differentiation Using Substitution

If lint 0∧ pi...

Question

If $\int_{0}^{π} x f (s i n x) d x = A \int_{0}^{\frac{π}{2}} f (s i n x) d x,$ then A=

2π

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π/4

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Solution

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Similar questions

(a) [- \frac{π}{2}, \frac{π}{2}] - \{0\} (b) [0, π] - \{\frac{π}{2}\} (c) (0, π) (d) (- \frac{π}{2}, \frac{π}{2})

\int_{0}^{π} x f (s i n x) d x =

\int_{0}^{π} x f (s i n x) d x

3 p

$\int_{0}^{π / 2} l o g (t a n x) d x =$

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