wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x26(x1)17(5x3)dx=x27.(x1)18k+c, where c is the constant of integration, then the value of k is


A

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

9


Differentiating both sides gives

x26.(x1)17(5x3)=1k[x27.18(x1)17+(x1)1827x26]

=x26(x1)17k[18x+27(x1)]

=x26(x1)17k(45x27)

=9x26(x1)17k(5x3)

k=9


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon