If Ksp(AgCl)=10−12Ksp(AgBr)=10−15, then the emf of the cell Ag(s)|AgBr(s)|Br−0.4M||Cl−2M|AgCl(s)|Ag(s) is
A
0V
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B
0.136V
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C
0.04135V
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D
Data insufficient
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Solution
The correct option is B0.136V AgCl(s)Ksp=10−12⇌Ag+(aq)+Cl−(aq) when [Cl−]=2M,Ag+=10−122M AgBr(s)Ksp=10−15⇌Ag+(aq)+Br−(aq) when [Br−]=0.4M,Ag+=10−150.4M For cell reaction Ag(s)|AgBr(s)|Br−(0.4M)||Cl−(2M)|AgCl(s)|Ag(s) Which is equivalent to Ag(s)|Ag+10−150.4||Ag+10−122|Ag(s) So cell reaction Ag(s)+Ag+(10−122)→Ag+(10−150.4)+Ag(s) which concentration cell Ecell=Eocell−0.0591nlogQc=0−0.05911log10−150.410−122=0.0591log10−22 Ecell=0.136V