If limx→ax9−a9x−a=9, find all possible values of a.
limx→ax9−a9x−a=9...(i)
LHS=limx→ax9−a9x−a
=9(a)9−1
=9a8
It is given that 9a8=9 [from (i)]
⇒a8=99=1
⇒a4=1
a2=1
a=±1
⇒a=1 and a =-1
If limx→ax9−a9x−a=limx→5(4+x), find all possible values of a.
If limx→ax5−a5x−a=405, find all possible values of a.