If ${log}_{10} m = b - {log}_{10} n$ , then $m =$

b / n

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b n

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10^{b} n

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b - 10^{n}

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10^{b} / n

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Solution

The correct option is E $10^{b} / n$
$b = {log}_{10} m + {log}_{10} n = {log}_{10} m n ∴ m n = 10^{b}; ∴ m = 10^{b} / n$ ; or
${log}_{10} m = {log}_{10} 10^{b} - {log}_{10} n = {log}_{10} (10^{b} / n), ∴ m = 10^{b} / n$ .

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