The correct option is C I and II only
For m = 1,
(1−1)(1−k)=0
0(1−k)=0
⇒0=0
m = 1 satisfies the following equation.
For k = 1,
(m−1)(1−1)=0
(m−1)0=0
⇒0=0
k = 1 satisfies the following equation.
For m = k,
(k−1)(1−k)≠0
m = k is not satisfying the following equation.
So, the condition I and II only are true.