If m -sin A -sin B find m -1- m -1tanA-B-2 A-B-2-sin A-B-sin A-BtanA-B-2 A-B-2sin A-B-sin A-B

The correct option is A tancot m = sinA/sinB m+1/m 1 = sinA+sinB/sinA sinB = 2sin(A+B)/2cos(A B)/2/2sin(A B)/2cos(A+B)/2 = tan(A+B)/2/tan(A B)/2 = tan(A+B)/2c ...

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Byju's Answer

Standard XI

Mathematics

Sin2a and Cos2a in Terms of Tana

If m =sin A /...

Question

If m = $\frac{s i n A}{s i n B}$ find $\frac{m + 1}{m - 1}$

tancot

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Solution

The correct option is A
tancot

m = $\frac{s i n A}{s i n B}$

$\frac{m + 1}{m - 1}$ = $\frac{s i n A + s i n B}{s i n A - s i n B}$

= $\frac{2 s i n \frac{(A + B)}{2} c o s \frac{(A - B)}{2}}{2 s i n \frac{(A - B)}{2} c o s \frac{(A + B)}{2}}$

= $\frac{t a n \frac{(A + B)}{2}}{t a n \frac{(A - B)}{2}}$ = tan $\frac{(A + B)}{2}$ cot $\frac{(A - B)}{2}$

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If m = sinAsinB find m+1m−1

The correct option is A tancot m = sinAsinB m+1m−1 = sinA+sinBsinA−sinB = 2sin(A+B)2cos(A−B)22sin(A−B)2cos(A+B)2 = tan(A+B)2tan(A−B)2 = tan(A+B)2cot(A−B)2

If m = $\frac{s i n A}{s i n B}$ find $\frac{m + 1}{m - 1}$