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Optical Fiber

If μ1=1.58 ...

Question

If $μ_{1} = 1.58$ and $μ_{2} = 1.53$ , what is $θ$ ?

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Solution

formula,

$sin θ = \frac{μ_{2}}{μ_{1}}$

$\Rightarrow θ = {sin}^{- 1} \frac{μ_{2}}{μ_{1}}$

$\Rightarrow θ = {sin}^{- 1} \frac{1.53}{1.58} = {sin}^{- 1} 0.968$

$∴ θ = 75.54$

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