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Question

If n=1, 2, 3, ..., then cos α cos 2 α cos 4 α ... cos 2n-1 α is equal to

(a) sin 2n α2n sin α

(b) sin 2n α2n sin 2n-1 α

(c) sin 4n-1 α4n-1 sin α

(d) sin 2n α2n sin α

(e) None of these

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Solution

(d) sin 2n α2n sin α

cos α cos 2 α cos 4α ... cos 2n-1 α=sin2nα2nsin α

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