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(x±a)(x±b) = x²±(a+b)x+ab.

If N=[(3+2*2^...

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If N=[{(3+22^1/2)^1/2+(3-22^1/2)^1/2}/(3^1/2+1)^1/2]-2(3^1/2-1)^1/2,then equals to

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3 \frac{1}{12} - [1 \frac{3}{4} + {2 \frac{1}{2} - (1 \frac{1}{2} - \frac{1}{3})}]

a : b = 1 \frac{1}{2} : 2 \frac{1}{4}

b : c = 2 : 3 \frac{1}{2}

a : b : c

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(i) (ii) (iii)

(iv) (v) (vi)

(vii) (viii)

\frac{\frac{1}{2} + 3 \frac{1}{4} + 1 \frac{1}{6}}{2 \frac{1}{2} + 1 \frac{1}{6} + 6 \frac{1}{3}} + \frac{1}{120}

P = 21 (21^{2} - 1^{2}) (21^{2} - 2^{2}) (21^{2} - 3^{2}) . . . (21^{2} - 10^{2})

P

is divisible by

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(x±a)(x±b) = x²±(a+b)x+ab.

Standard IX Mathematics

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