If n -700- n A -200- n B -300- n A - B -100- then n A - B -A- 300B- 500C- 240D- 400

The correct option is A 300 GIven, n(∪)= 700, n(A) = 200, n(B) = 300 , n(A∩ B) = 100 We know that, n(A ∪ B) = n(A) + n(B) n(A∩ B) n(A ∪ B) = 200 +300 100 n ...

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Byju's Answer

Standard VIII

Mathematics

Complement of a Set

If n ∪=700, n...

Question

If $n (\cup) = 700$ , $n (A) = 200$ , $n (B) = 300$ , $n (A \cap B) = 100$ , then $n (A^{^{'}} \cap B^{^{'}})$

400

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240

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300

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500

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Solution

The correct option is C
300

GIven, $n (\cup)$ = 700, $n (A) = 200$ , $n (B) = 300$ , $n (A \cap B) = 100$

We know that,
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$
$n (A \cup B) = 200 + 300 - 100$
$n (A \cup B) = 400$

Now,
$n (A^{^{'}} \cap B^{^{'}}$ ) = $n (U) - n (A \cup B)$
$n (A^{^{'}} \cap B^{^{'}}$ ) = $700 - 400 = 300$

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If n(∪)=700, n(A)=200, n(B)=300 , n(A∩B)=100, then n(A′∩B′)

The correct option is C 300 GIven, n(∪)= 700, n(A)=200, n(B)=300 , n(A∩B)=100 We know that, n(A∪B)=n(A)+n(B)−n(A∩B) n(A∪B)=200+300−100 n(A∪B)=400 Now, n(A′∩B′) = n(U)−n(A∪B) n(A′∩B′) = 700−400=300

If $n (\cup) = 700$ , $n (A) = 200$ , $n (B) = 300$ , $n (A \cap B) = 100$ , then $n (A^{^{'}} \cap B^{^{'}})$