If n ∈ N, then 11n+2 + 122n+1 is divisible by
113
123
133
None of these
Putting n = 1 in 11n+2+122n+1
We get, 111+2+122×1+1 = 113+123 = 3059, which
is divisible by 133.
11n+2+122n+1 is divisible by 133 for all nϵN.