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Question

If nPr=720 and nCr=120. Find r.

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Solution

As, nPr=720, then,

n!(nr)!=720 (1)

And,

nCr=120

n!r!(nr)!=120

From equation (1),

1r!×720=120

r!=6

r!=3×2×1

r!=3!

r=3


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