If $^{n} C_{8} =^{n} C_{2}$ , find the value of $^{n} C_{2}$ .

10

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2

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45

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8

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Solution

The correct option is C $45$
$^{n} C_{8} =^{n} C_{2} t h e n n = 8 + 2 = 10 ∴^{n} C_{2} =^{10} C_{2} = (\frac{10!}{(10 - 2)!}) \cdot 2! = (\frac{10!}{8! \cdot 2}) = (\frac{10 \cdot 9}{2}) = 45$

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Similar questions

If $^{n} C_{8} =^{n} C_{2},$ find $^{n} C_{2} .$

^{n} C_{8} =^{n} C_{2}

^{n} C_{2}

^{n} C_{8} =^{n} C_{2}

n

a =^{n} C_{0} +^{n} C_{3} +^{n} C_{6} + . . .

b =^{n} C_{1} +^{n} C_{2} +^{n} C_{4} +^{n} C_{5} +^{n} C_{7} +^{n} C_{8} + . . .

c =^{n} C_{1} -^{n} C_{2} +^{n} C_{4} -^{n} C_{5} +^{n} C_{7} -^{n} C_{8} + . . .

{(a - \frac{b}{2})}^{2} + \frac{3 c^{2}}{4}

a =^{n} C_{0} +^{n} C_{3} +^{n} C_{6} + . . .

b =^{n} C_{1} +^{n} C_{2} +^{n} C_{4} +^{n} C_{5} +^{n} C_{7} +^{n} C_{8} + . . .

c =^{n} C_{1} -^{n} C_{2} +^{n} C_{4} -^{n} C_{5} +^{n} C_{7} -^{n} C_{8} + . . .

{(a - \frac{b}{2})}^{2} + \frac{3 c^{2}}{4}

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