If nP4 = 30nC5, then n =
6
7
8
9
nP4nC5 = 30⇒n!(n−4)!×5!.(n−5)!n! = 30
⇒(n−4) = 4⇒n = 8
If the coefficients of Tr,Tr+1,Tr+2 terms of (1+x)14 are in A.P., then r =
If nP3+nCn−2 = 14n, then n =
5+9+13+.......upto n. termsIf 7+9+11+..... upto (n+1) terms=1716 then n is equal to