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Current Loop Is a Magnet?

If Oxygen and...

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If Oxygen and iron both has equal magnetic moment since they have four unpaired electrons , does it mean that oxygen is magnetic?

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The substances which contain species with unpaired electrons in
their orbitals behave as paramagnetic substances. Such substances
are weakly attracted by the magnetic field. The paramagnetism is
expressed in terms of magnetic moment. The magnetic moment is
related to the number of unpaired electrons according to the
following relation:
Magnetic moment,

μ = \sqrt{n (n + 2)} B M

n =

number of unpaired electrons.

B M

stands for Bohr magneton, a unit of magnetic moment.

1 B M = \frac{e h}{4 π m c} = 9.27 \times 10^{- 24} {A m}^{2}

J T^{- 1}

Which of the following ions has magnetic moment equal to that of

{T i}^{3 +}

?

Q. Assertion :The magnetic moment of

M g

-atom is more than

K

-atom as the former has two electrons in outermost shell. Reason: The magnetic moment of

N

-atom is more than magnetic moment of

O

-atom and former has more number of unpaired electrons.

[F e (H_{2} O)_{4} (C N)_{2}]

is the empirical formula of a compound which has a magnetic moment corresponding to

2 \frac{2}{3}

unpaired electrons per iron. The best possible formula of the compound is

If hydrogen atoms (in the ground state) are passed through an homogeneous magnetic field, the beam is split into two parts. This interaction with the magnetic field shows that the atoms must have magnetic moment. However, the moment cannot be due to the orbital angular momentum since

φ = 0

. Hence one must assume existence of intrinsic angular momentum, which as the experiment shows, has only two permitted orientations.
Spin of the electron produces angular momentum equal to

s = \sqrt{s (s + 1)} \frac{h}{2 π}

s = + \frac{1}{2}

Total spin of an atom

= + \frac{n}{2} o r - \frac{n}{2}

where n is the number of unpaired electron.
The Substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment.
The magnetic moment of an atom

μ = \sqrt{s (s + 1)} \frac{e h}{2 π m c} = \sqrt{\frac{n}{2} (\frac{n}{2} + 1)} \frac{e h}{2 π m c}

s = \frac{n}{2}

μ_{s} = \sqrt{n (n + 2)}

B.M
n-number of upaired electrons
1.B.M. (Bohr magneton)

= \frac{e h}{4 π m c}

If magnetic moment is zero the substance is di-magnetic.

Which of the following ion has highest magnetic moment?

Q. Calculate the maximum spin and the spin magnetic moment (in B.M.) for the atom having 6 unpaired electrons.

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