Question

If P(A) = 0.2, P(B’) = 0.6 and P(A$\cap$B)= 0.1. Find P(A$\cup$B).

Answer 1

P(A) = 0.2,

P(B’) = 0.6

$\Rightarrow$ P(B) = 1 – P(B’)

= 1 – 0.6

= 0.4

P(A$\cap$B)= 0.1

P(A$\cup$B) = P(A) + P(B) – P(A∩B)

= 0.2 + 0.4 – 0.1

= 0.5