If P = {x:x ∈ W and 4 ≤ x≤ 8}, and Q = {x:x ∈ N and x < 6}. Find : (i) P∪Q and P∩Q (ii) Is (P∪Q)⊃(P∩Q)
(i) P = (4, 5, 6, 7, 8) Q = (1, 2, 3, 4, 5) P∪Q = (1, 2, 3, 4, 5, 6, 7, 8) (P∩Q) = (4, 5)
(ii) Yes, all the element of set P∪Q are contained in the set (P∩Q). Therefore P∪Q is a proper subset of (P∩Q).