If pth,qth,rth terms of a G.P. are the positive numbers a,b and c, then the angle between the vectors (loga2)^i+(logb2)^j+(logc2)^k and (q−r)^i+(r−p)^j+(p−q)^k is
A
π2
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B
π3
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C
sin−1√a2+b2+c2
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D
sin−1√p2+q2+r2
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Solution
The correct option is Aπ2 Let first term of G.P. be x0 and the common ratio be x ⇒a=x0xp−1⇒loga=logx0+(p−1)logx⋯(i)
Similarly logb=logx0+(q−1)logx⋯(ii) and logc=logx0+(r−1)logx⋯(iii)
Let →y=(loga2)^i+(logb2)^j+(logc2)^k and →z=(q−r)^i+(r−p)^j+(p−q)^k ⇒→y⋅→z=2loga(q−r)+2logb(r−p)+2logc(p−q)
Using (i),(ii) and (iii), we have ⇒→y⋅→z=2(q−r)(logx0+(p−1)logx)+2(r−p)(logx0+(q−1)logx)+2(p−q)(logx0+(r−1)logx) ⇒→y⋅→z=2logx0(q−r+r−p+p−q)+2logx(qp−pr−q+r+qr−pq−r+p+pr−qr−p+q) ⇒→y⋅→z=0 ∴ Angle between two given vectors is π2