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Question

If pth,qth,rth terms of a G.P. are the positive numbers a,b and c, then the angle between the vectors (loga2)^i+(logb2)^j+(logc2)^k and (qr)^i+(rp)^j+(pq)^k is

A
π2
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B
π3
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C
sin1a2+b2+c2
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D
sin1p2+q2+r2
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Solution

The correct option is A π2
Let first term of G.P. be x0 and the common ratio be x
a=x0xp1loga=logx0+(p1)logx (i)
Similarly
logb=logx0+(q1)logx (ii) and logc=logx0+(r1)logx (iii)

Let y=(loga2)^i+(logb2)^j+(logc2)^k and z=(qr)^i+(rp)^j+(pq)^k
yz=2loga(qr)+2logb(rp)+2logc(pq)
Using (i),(ii) and (iii), we have
yz=2(qr)(logx0+(p1)logx)+2(rp)(logx0+(q1)logx)+2(pq)(logx0+(r1)logx)
yz=2logx0(qr+rp+pq)+2logx(qpprq+r+qrpqr+p+prqrp+q)
yz=0
Angle between two given vectors is π2

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