If $p (x) = 5 - 4 x + 2 x^{2}$ , find

(i) p(0)

(ii) p(3),

(iii) p(-2)

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Solution

$p (x) = 5 - 4 x + 2 x^{2} = 2 x^{2} - 4 x + 5$

(i) $p (0) = 2 \times (0)^{2} - 4 \times 0 + 5 = 0 - 0 + 5 = 5$

(ii) $p (3) = 2 \times (3)^{2} - 4 \times 3 + 5 = 2 \times 9 - 12 + 5 = 18 - 12 + 5 = 11$

(iii) $p (- 2) = 2 \times (- 2)^{2} - 4 \times - 2 + 5 = 2 \times 4 + 8 + 5 = 8 + 8 + 5 = 21$

Hence,

p(0) = 5 , p(3) = 11 and p(-2) = 21.

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