If P(x)=a0+a1x2+a2x4+.......+anx2n be a polynomial in x∈R with 0<a1<a2<.......<an, then P(x) has-
A
no point of minimum
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B
only one point of minimum
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C
only two points of minimum
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D
None of these
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Solution
The correct option is B only one point of minimum Given P(x)=a0+a1x2+a2x4+.......+anx2n P′(x)=2xa1+4a2x3+.......+2nanx2n−1 For max. or min. P′(x)=0 ⇒2x[a1+2a2x2+.......+n.anx2n−2]=0 ⇒x=0 Now P′′(x)=2a1+12a2x2+........+2n(2n−1)anx2n−2 ⇒P′′(x)=2a1>0 (given a1>0) Hence, P(x) has only one minimum at x=0