If P x -1-5 x -1-5 x - Q x -1-5 x -1-5 x- then P x - Q x will beA- B- 1-25 x2-1-25 x x2C- 1 T-1-5 xD- 1-25 x2-1-25 x2

The correct option is C (1+5x)^2/(1 5x)^2Given, P(x) =1+5x/1 5x and Q(x) =1 5x/1+5x nbsp; ∴ P(x)/Q(x) = 1+5x/1 5x/1 5x/1+5x = (1+5x)(1+5x)/(1 5x)(1 5x) = ( ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Addition and Subtraction of Algebraic Expression

If P x =1+5 x...

Question

If $P (x) = \frac{1 + 5 x}{1 - 5 x} & Q (x) = \frac{1 - 5 x}{1 + 5 x},$ then $\frac{P (x)}{Q (x)}$ will be

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1 - 25 x^{2}}{1 + 25 x^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{(1 + 5 x)^{2}}{(1 - 5 x)^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1 + 25 x^{2}}{1 - 25 x^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{(1 + 5 x)^{2}}{(1 - 5 x)^{2}}$
Given, $P (x) = \frac{1 + 5 x}{1 - 5 x}$
$a n d Q (x) = \frac{1 - 5 x}{1 + 5 x}$

$∴ \frac{P (x)}{Q (x)} = \frac{\frac{1 + 5 x}{1 - 5 x}}{\frac{1 - 5 x}{1 + 5 x}} = \frac{(1 + 5 x) (1 + 5 x)}{(1 - 5 x) (1 - 5 x)} = \frac{(1 + 5 x)^{2}}{(1 - 5 x)^{2}}$

Suggest Corrections

Similar questions

Q. If

P (x) = \frac{1 + 5 x}{1 - 5 x} & Q (x) = \frac{1 - 5 x}{1 + 5 x},

then

\frac{P (x)}{Q (x)}

will be

Q. If

5 x + \frac{1}{5 x} = 23

and

5 x - \frac{1}{5 x} = 17

, find the value of

25 x^{2} - \frac{1}{25} x^{2}

Q. State whether the statement is True or False.

The square of

(5 x + \frac{1}{5 x})

is equal to

25 x^{2} + 2 + \frac{1}{25 x^{2}}

Q. If

(x^{2} + \frac{1}{25 x^{2}}) = 9 \frac{2}{5}

, find the value of

(x + \frac{1}{5 x})

Now for each pair of polynomials p(x) and q(x) given below, find p(x) + q(x) and p(x) − q(x). Also compute p(1) + q(1) and p(1) − q(1) for each.

(i)

(ii)

(iii)

(iv)

(v)

Join BYJU'S Learning Program

If P(x)=1+5x1−5x & Q(x)=1−5x1+5x, then P(x)Q(x) will be

The correct option is C (1+5x)2(1−5x)2Given, P(x)=1+5x1−5x and Q(x)=1−5x1+5x ∴ P(x)Q(x)=1+5x1−5x1−5x1+5x=(1+5x)(1+5x)(1−5x)(1−5x)=(1+5x)2(1−5x)2

If $P (x) = \frac{1 + 5 x}{1 - 5 x} & Q (x) = \frac{1 - 5 x}{1 + 5 x},$ then $\frac{P (x)}{Q (x)}$ will be