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Question

If p(x)=x22x+1, q(x)=x41 and r(x)=x32x25x+6, find their HCF.

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Solution

We factorise all of them:
p(x)=x22x+1=(x1)2,
q(x)=x41=(x21)(x2+1)=(x1)(x+1)(x2+1),
r(x)=x32x25x+6=x3x2+x6x+6
=x2(x1)x(x1)6(x1)
=(x1)(x2x6)=(x1)(x3)(x+2).
Observe that HCF(p(x),q(x))=x1 and HCF(x1,r(x))=x1. Hence the HCF of p(x),q(x),r(x) is x1.

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