If $p (y) = 4 + 3 y - y^{2} + 5 y^{3}$ , find
(i) p(0),
(ii) p(2),
(iii) p(-1)

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Solution

If $p (y) = 4 + 3 y - y^{2} + 5 y^{3}$ ,

(i) $p (0) = 4 + 3 (0) - (0)^{2} + 5 (0)^{3} = 4$

(ii) $p (2) = 4 + 3 (2) - (2)^{2} + 5 (2)^{3} = 4 + 6 - 4 + 40 = 46$

(iii) $p (- 1) = 4 + 3 (- 1) - (- 1)^{2} + 5 (- 1)^{3} = 4 - 3 - 1 - 5 = - 5$

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