If R2-6k then- Prove that - R-2 -3

Consider the given equation, #10; #10; R^2=6k #10; #10;Put, k=0,1,2,3,...... #10; #10;Put, k=0 we get #10; #10; R=0 #10; ...

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If R2=6k th...

Question

If $R^{2} = 6 k$ then, Prove that : $R = 2 \sqrt{3}$

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u = f (r)

r^{2} = x^{2} + y^{2} + z^{2}

\frac{\partial^{2} u}{\partial x^{2}} + \frac{\partial^{2} u}{\partial y^{2}} + \frac{\partial^{2} u}{\partial z^{2}} = f^{''} (r) + \frac{2}{r} f (r)

^{n} C_{n - r} + 3^{n} C_{n - r + 1} + 3^{n} C_{n - r + 2} +^{n} C_{n - r + 3} =^{p} C_{r}

p = n + 3

r_{1}

r_{2}

r_{3}

r_{1} = r_{2} + r_{3} + r,

\frac{1}{r_{1}} + \frac{1}{r_{2}} + \frac{1}{r_{3}} = \frac{1}{r}

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