Domain and Range of Basic Inverse Trigonometric Functions
If sin-1x+sin...
Question
If (sin−1x+sin−1w)(sin−1y+sin−1z)=π2, then D=∣∣∣xN1yN2zN3wN4∣∣∣, (N1,N2,N3,N4∈N)
A
has a maximum value of 2
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B
has a minimum value of 0
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C
16 different D are possible
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D
has a minimum value of −2
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Solution
The correct options are A has a maximum value of 2 C16 different D are possible D has a minimum value of −2 (sin−1x+sin−1w)(sin−1y+sin−1z)=π2 ∴sin−1x+sin−1w=sin−1y+sin−1z=π sin−1x+sin−1w=sin−1y+sin−1z=−π ∴x=y=z=w=1 or x=y=z=w=−1 Hence, the maximum value of ∣∣∣xN1yN2zN3wN4∣∣∣=∣∣∣1−111∣∣∣=2 and minimum value ∣∣∣−1111∣∣∣=−2. Also, there are 16 different determinants as each palce value is either 1 or −1.