If $s i n^{2} (3 x + 45) + c o s^{2} (2 x + 60) = 1$ then $x =$ ...............

60

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $15$
$s i n^{2} (3 x + 45) + c o s^{2} (2 x + 60) = 1$
$∴ s i n^{2} (3 x + 45) = 1 - c o s^{2} (2 x + 60)$
$∴ s i n^{2} (3 x + 45) = s i n^{2} (2 x + 60)$ ............. [since $1 - c o s^{2} θ = s i n^{2} θ$ ]
$∴ 3 x + 45 = 2 x + 60$
$∴ x = 15$

Suggest Corrections

Similar questions

{sin}^{2} (3 x + 45) + {cos}^{2} (2 x + 60) = 1

x =

If $c o t 3 x = s i n 45^{\circ} c o s 45^{\circ} + c o s 60^{\circ}$ and $0 < x \leq 90^{\circ}$ , then $x$ = __________________

\sqrt{3} \tan 2 θ - 3 = 0 then θ = ?

\sqrt{3}

Join BYJU'S Learning Program