If sin⁡(A+B) = 1 and sin⁡(A-B) = 1/2, 0 ≤ A+B ≤ 90° and A > B, then find A and B.

A=60° and B=30°

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A=30° and B=60°

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A=90° and B=0°

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A=45° and B=45°

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Solution

The correct option is A
A=60° and B=30°

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Similar questions

If sin⁡(A + B) = 1 and sin ⁡(A -B) = $\frac{1}{2}$ , such that 0 ≤ A + B ≤ 90° and A > B, then find A and B.

\frac{1}{2}

\frac{1}{\sqrt 2}

\frac{1}{sin (x - a) sin (x - b)} = \frac{cot (x - a) - cot (x - b)}{sin (a - b)}

(i i)

\frac{1}{cos (x - a) cos (x - b)} = \frac{tan (x - b) - tan (x - a)}{sin (a - b)}

cos A + sin B = m

sin A + cos B = n,

2 sin (A + B) = m^{2} + n^{2} - 2.

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