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Question

If sin(B+CA),sin(C+AB),sin(A+BC) are in A.P., then cot A, cotB, cotC are in


A

GP

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B

HP

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C

AP

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D

None of these

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Solution

The correct option is B

HP


Given:
sin(B+CA),sin(C+AB),sin(A+BC)areinA.Psin(C+AB)sin(B+CA)=sin(A+BC)sin(C+AB)2sin(C+ABBC+A2)COS(C+AB+B+CA2)=2sin(A+BCCA+B2)cos(A+BC+C+AB2)sin(AB)cosC=sin(BC)cosAsinA cosB cosCcosA sinB cosCsinB cosC cosAcosB sinC cosA2sinB cosA cosC=sinA cosB cosC+cosA cosB sinCDividingbothsidesbycosA cosB cosC:2tanB=tanA+tanC2cotB=1cotA+1cotC


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