If -1849-0-06-x2-43-25- then x isA- 0-0025B- 0-015C- 0-05D- 0-025

The correct option is C 0.05 [ 43 + √(0.06 + x^2) = 43.25 ⇒√(0.06 + x^2) = 0.25 ⇒x^2 = 0.0625 0.06; x = √(0. ...

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Standard XII

Physics

RLC Circuit

If √1849+√0.0...

Question

If $\sqrt{1849} + \sqrt{0.06 + x^{2}} = 43.25$ , then x is

0.0025

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0.015

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0.05

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0.025

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Solution

The correct option is C
0.05

$\begin{matrix} 43 + \sqrt{0.06 + x^{2}} = 43.25 \Rightarrow \sqrt{0.06 + x^{2}} = 0.25 \Rightarrow x^{2} = 0.0625 - 0.06 x = \sqrt{0.0025} = 0.05 \end{matrix}$

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If √1849+√0.06+x2=43.25, then x is

The correct option is C 0.05 43+√0.06+x2=43.25⇒√0.06+x2=0.25⇒x2=0.0625−0.06x=√0.0025=0.05

If $\sqrt{1849} + \sqrt{0.06 + x^{2}} = 43.25$ , then x is

The correct option is C
0.05

$\begin{matrix} 43 + \sqrt{0.06 + x^{2}} = 43.25 \Rightarrow \sqrt{0.06 + x^{2}} = 0.25 \Rightarrow x^{2} = 0.0625 - 0.06 x = \sqrt{0.0025} = 0.05 \end{matrix}$