If t1- t2- t3- t4- t5 be in A-P- of common difference d then the value of D- - t2t3 t2 t1- t3t4 t3 t2- t4t5 t4 t3- - - is 2d4-

The correct option is A TrueApply R_3 R_2, R_2 R_1 #160; t_5 t_3= t_4 t_2 =2d D = |[ t_2t_3 amp; t_2 amp; t_1; t_3(2d) amp; d amp; d; ...

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Properties of Determinants

If t1, t2, ...

Question

If $t_{1}, t_{2}, t_{3}, t_{4}, t_{5}$ be in A.P. of common difference d then the value of
$D =$ $∣ ∣ ∣ ∣ \begin{matrix} t_{2} t_{3} & t_{2} & t_{1} t_{3} t_{4} & t_{3} & t_{2} t_{4} t_{5} & t_{4} & t_{3} \end{matrix} ∣ ∣ ∣ ∣$ is $2 d^{4}$ .

True

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False

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T_{0}, T_{1}, T_{2}, . . . . . T_{n}

(x + a)^{n}

(T_{0} - T_{2} + T_{4} - T_{6} + . . . . .)^{2} + (T_{1} - T_{3} + T_{5} + . . . . .)^{2}

T_{0}, T_{1}, \dots, T_{n}

(x + a)^{n}

(T_{0} - T_{2} + T_{4} - \dots)^{2} + (T_{1} - T_{3} + T_{5} - \dots)^{2}

T_{0}, T_{1}, T_{2}, . . ., T_{n}

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{(T_{0} - T_{2} + T_{4} - T_{6} + . . .)}_{0}^{2} + {(T_{1} - T_{3} + T_{5} + . . .)}_{1}^{2}

A . P

a = 2

t_{5} = 12

t_{2}, t_{3}, t_{4}

S_{1} = T_{1} + T_{2} + T_{3} +

+ T_{n}

S_{2} = T_{1} + T_{3} + T_{5} +

+ T_{n}

S_{1} / S_{2} =

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