If tan2450−cos2300=xsin450cos450,thenx=?
1/2
-1/2
1
√3 /2
12−(√32)2=x×1√2×1√2⇒1−34=x2⇒x=12
If tan2450−cos2300=xsin450cos450,then x=?
If x = √2+√1, then the value of [x+1x] is ?