If tan x tan y-a and x-y-6- then tan x and tan y satisfy the equation

The correct option is A If tan x tan y = a and x + y =π/6tan π/6=tan(x+y)=tan x+tan y/1 a 1 a/√(3)=tan x+tan y so x and y satisfies √(3)x^2 (1 a)x+a √(3)=0 ...

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Standard XII

Mathematics

Integration by Partial Fractions

If tan x tan ...

Question

If tan x tan y = a and x + y = $\frac{π}{6}$ , then tan x and tan y satisfy the equation

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Solution

The correct option is B

If tan x tan y = a and x + y $= \frac{π}{6} t a n \frac{π}{6} = t a n (x + y) = \frac{t a n x + t a n y}{1 - a}$

$\frac{1 - a}{\sqrt{3}} = t a n x + t a n y s o x a n d y s a t i s f i e s \sqrt{3} x^{2} - (1 - a) x + a \sqrt{3} = 0$

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If tan x tan y = a and x + y = π6 , then tan x and tan y satisfy the equation

The correct option is B If tan x tan y = a and x + y =π6tan π6=tan(x+y)=tan x+tan y1−a 1−a√3=tan x+tan y so x and y satisfies √3x2−(1−a)x+a√3=0

If tan x tan y = a and x + y = $\frac{π}{6}$ , then tan x and tan y satisfy the equation

The correct option is B

If tan x tan y = a and x + y $= \frac{π}{6} t a n \frac{π}{6} = t a n (x + y) = \frac{t a n x + t a n y}{1 - a}$

$\frac{1 - a}{\sqrt{3}} = t a n x + t a n y s o x a n d y s a t i s f i e s \sqrt{3} x^{2} - (1 - a) x + a \sqrt{3} = 0$