. If tanA-tanB=x & cotB-cotA=y, then prove that cot(A-B) =1/x + 1/y

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Prove that : $\frac{t a n A - t a n B}{c o t B - c o t A} = \frac{t a n B}{c o t A}$

\frac{c o t A + t a n B}{c o t B + t a n A} = c o t A t a n B

If A + B = $225^{\circ}$ , then $\frac{c o t A}{1 + c o t A}$ . $\frac{c o t B}{1 + c o t B}$ =

tan A - tan B = x, cot B - cot A = y

cot (A - B) = (\frac{1}{x}) + (\frac{1}{y})

tan A - tan B = x

cot B - cot A = y

cot (A - B) = \frac{1}{x} + \frac{1}{y}

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