If the conjugate of (x+iy)(1-2i) be 1+i, then:
x-iy=1-i1+2i
x+iy=1-i1-2i
x=35
y=15
Explanation for the correct option.
Step 1: Write the conjugate of (x+iy)(1-2i)
Now conjugate is (x-iy)(1+2i)
According to the given information⇒(x-iy)(1+2i)=1+i⇒x-iy=1+i1+2i⇒x-iy=(1+i)(1-2i)5⇒x-iy=3-i5Step 2: Comparing real and imaginary parts on both sides
⇒x-iy=35-i5⇒x=35,y=15
Hence, options C & D are correct.
If the conjugate of (x+iy)(1-2i) be 1+i, then