If the equation $2 x^{2} + 3 x y + b y^{2} - 11 x + 13 y + c = 0$ represents two perpendicular straight lines, then

b = - 2

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b = 2

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c = - 2

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c = 2

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Solution

The correct option is A $b = - 2$
$2 x^{2} + 3 x y + b y^{2} - 11 + 13 y + c = 0 - (1)$
$Eq (1) represents two perpendicular straight lines$
$then m_{1} m_{2} = - 1$
$m_{1} m_{2} = \frac{2}{b} = - 1$
$b = - 2$

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