If the equation anxn+an−1xn−1+.........+a1x=0,a1≠0,n≥2, has a positive root~ x=α, then the equation nanxn−1+(n−1)an−1xn−2+.......+a1=0 has a positive root, which is :
Let f(x)=anxn+an−1xn−1+.....+a1x
∴f(0)=0
f(α)=0
⇒f′(x)=0 has least one root between (0,α)
⇒n anxn−1+(n−1)an−1xn−1+.....+a1=0 has a positive root smaller than α.