If the line
$(3 x + 14 y + 7) + k (5 x + 7 y + 6) = 0$
is parallel to the y-axis, then the value of $k$ is

\frac{1}{3}

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\frac{- 3}{5}

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Solution

The correct option is C $- 2$
Given line is $(3 x + 14 y + 7) + k (5 x + 7 y + 6) = 0$

$\Rightarrow (3 + 5 k) x + (14 + 7 k) y + (7 + 6 k) = 0$

If it is parallel to y- axis, then coefficient of y $= 0$

$\Rightarrow 14 + 7 k = 0$

$\Rightarrow k = - 2$

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