If the lines 2x + y- 3 = 0, 5x + ky – 3 = 0 and 3x – y – 2 = 0 are concurrent,then the value of k is

-1

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-2

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Solution

The correct option is B
-2

Solving 2x + y – 3 = 0 and 3x – y – 2 = 0, we have (x, y) = (1, 1)

(1, 1) lies 5x + 5y – 3 = 0

$\Rightarrow$ K + 2 = 0

K = – 2

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Similar questions

2 x + y - 3 = 0, 5 x + k y - 3 = 0

3 x - y - 2 = 0

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L_{1} : 2 x + y - 3 = 0

L_{2} : 5 x + k y - 3 = 0

L_{3} : 3 x - y - 2 = 0

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k x + 2 y + 2 = 0,

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a

2 x + y - 1 = 0 a x + 3 y - 3 = 0 3 x + 2 y - 2 = 0

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